Question

The base of
anisoscelsen triangle measure 80cm and its aera 360cm. find parimeter.

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Answer 1

Step-by-step explanation:

please support this answer

Answer 2

Answer:

Let us assume the equal sides to be x.

Given that base=80 cm.

=> Height of the isosceles triangle=\sqrt{x^{2}-40^{2}}

x

2

−40

2

(using pythagoras theorem)

So, area=\frac{1}{2}bh

2

1

bh

360=\frac{1}{2}*80*\sqrt{x^{2}-40^{2}}

2

1

∗80∗

x

2

−40

2

9=\sqrt{x^{2}-40^{2}}

x

2

−40

2

81={x^{2}-40^{2}}x

2

−40

2

x^{2}=1681

x=41cm

=> Perimeter=41+41+80=162cm.

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