The base of isosceles triangle is 10cm and one of its equal sides is 13cm. Find the area using Herons 's formula.
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Given:-
- Base of the triangle = 10 cm
- Equal sides of the triangle = 13 cm
To Find:-
- Find the area using Heron's formula
Solution:-
Sides of the triangle:-
a = 10 cm
b = 13 cm
c = 13 cm
To find area using Heron's formula we first need to find the semi-perimeter of the given sides of the triangle,
We know,
✭ s = (a + b + c)/2
Hence,
s = (10 + 13 + 13)/2
=> s = (10 + 26)/2
=> s = 36/2
=> s = 18
Now,
Applying Heron's formula,
We know,
✭ A = √s(s - a) (s - b) (s - c)
Hence,
A = √18(18 - 10) (18 - 13) (18 - 13)
=> A = √18 × 8 × 5 × 5
=> A = √2 × 3 × 3 × 2 × 2 × 2 × 5 × 5
=> A = 2 × 2 × 3 × 5
=> A = 60 cm²
Therefore the area of this isosceles triangle is 60 cm².
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