Question

The base of isosceles triangle is 12 cm and it's perimeter is 32cm. Find its area​

Answer 1

ISOSCELES TRIANGLE HAVE TWO SIDES EQUAL AND ONE UNEQUAL..

SO .. THIRD SIDE LET BE x

12+12+x=32

24x=23

x=32/24

x=4/3

Hope it's help you

Answer 2

Question

1. The base of an isosceles triangle is 12 cm and it's perimeter is 32 cm. Find the area of the triangle.

Solution

Let each of the two equal sides of the given isosceles triangle be x cm.

Since, perimeter of the triangle is 32 cm

⟹ x + x + 12 = 32 ⟹ x = 10

Hence, the sides of the given isosceles triangle are 10 cm, 10 cm and 12 cm

Let a = 10 cm, b = 10 cm and c = 12 cm

$\sf{s=\dfrac{a+b+c}{2}=\dfrac{10+10+12}{2} \: cm=16 \: cm} \\ \sf{Area \: of \: the \: ∆= \sqrt{s(s-a)(s-b)(s-c)} } \\ \\ \sf{= \sqrt{16(16-10)(16-10)(16-12)} cm^{2}} \\ \\ \sf{ \sqrt{16×6×6×4} \: cm²=4×6×2 \: cm²=48 \: cm²}$

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