Question

The base of isosceles triangle is 4/3 cm the perimeter of triangle is 4 2/15 cm what is the length of either of the remaining equal sides​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

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$\green{\underline \bold{Given :}}$

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• Base = $\rm \dfrac { 4 } { 3 }$ cm

• Perimeter = $\rm 4 \dfrac { 2 } { 15 }$

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$\red{\underline \bold{To \: Find:}}$

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• Length of the other two equal sides.

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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Let the other 2 equal sides be of 'x' length.

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$\underline{\bold{\texttt{Perimeter of triangle :}}}$

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Perimeter = Side 1 + Side 2 + Side 3

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$\rm \longmapsto 4 \dfrac { 2 } { 15 } = x + x + \dfrac { 4 } { 3 }$

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$\rm \longmapsto \dfrac { 62 } { 15 } = 2x + \dfrac { 4 } { 3 }$

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$\rm \longmapsto \dfrac { 62 } { 15 } = \dfrac { 6x + 4 } { 3 }$

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$\underline{\bold{\texttt{Cross multiplying }}}$

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$\sf \longmapsto 186 = 90x + 60$

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$\sf \longmapsto 90x = 126$

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$\sf \longmapsto x = \dfrac { 126 } { 90 }$

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$\sf \longmapsto x = \dfrac { 7 } { 5 } cm$

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Hence the length of equal sides is $\sf \dfrac { 7 } { 5 } cm$

$\rule{200}5$

Answer 2

Step-by-step explanation:

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