Question

The base of parallelogram is 2x+3 units and corresponding height is 2x-3units.Find the area of the parallelogram in terms of x.What will be the area of parallelogram if x=30 units.

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Answer 1

The answer is given below :

The base of the parallelogram is (2x + 3) units

and

the corresponding height is (2x - 3) units.

So, the area of the parallelogram is

= base × height

= (2x + 3)(2x - 3) unit²

= (4x² - 9) unit²

[using the identity (a+b)(a-b) = a² - b².]

Now, when x = 30 units, the area of the parallelogram be

= (4×30² - 9) unit²

= (4×900 - 9) unit²

= (3600 - 9) unit²

= 3591 unit²

Thank you, sister for your question

Answer 2

↑ Here is your answer ↓
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Formula for area of parallelogram,

$= b*h$

Given that,

$b = 2x+3$

$h = 2x-3$

Sub the values now,

$= (2x+3)(2x-3)$

$= (2x)^2 - (3)^2$

$= 4x^2 - 9$

This is the value in terms of 'x'

Now if 'x' is 30 units,

$= 4(30)^2 - 9$

$= 4(900) - 9$

$= 3600 - 9$

So,

$= 3591$