Question

the base of parallelogram is twice its height and its area is 128cm2. Find the height and base of the parallelogram​

Answer 1

Answer:

hight is 16cm

base is 32cm

Step-by-step explanation:

Given :Base of parallelogramb=2×height

Area of parallelogram=b×h=512cm2

⇒2h×h=512cm2

⇒h2=256

⇒h=16cm

Base=2h=2×16=32cm

Answer 2

Answer :

• Base of parallelogram = 16cm
• Height of parallelogram = 8cm

Given :

• The base of parallelogram is twice its height
• Area is 128cm²

To find :

• Height and base of parallelogram

Solution :

Given, The base of parallelogram is twice its height so,

• Let the base be 2x
• Let the height be x

We know that

• Area of parallelogram = b × h

Where,

• b is base of parallelogram
• h is height of parallelogram

Given, Area is 128cm²

According to question :

➠ Area of parallelogram = b × h

➠ 128 = 2x × x

➠ 128 = 2x²

➠ 2x² = 128

➠ x² = 128/2

➠ x² = 64

➠ x = √64

➠ x = 8cm

Finding the base and height of parallelogram :

➠ Base of parallelogram = 2x

➠ Base of parallelogram = 2(8)

➠ Base of parallelogram = 16cm

➠ Height of parallelogram = x

➠ Height of parallelogram = 8cm

Hence,

• Base of parallelogram = 16cm
• Height of parallelogram = 8cm

Verification :

➠ 128 = 2x × x

➠ 128 = 2(8) × 8

➠ 128 = 16 × 8

➠ 128 = 128

Hence verified