the base of parallelogram is twice its height if the area of parallelogram is 512 CM square find the base and height
Answers
Answered by
18
Answer:16
Step-by-step explanation:
Area of parallelogram =bh
base(b)=2*h
So, 2h*h=512
h^2=512/2
h^2=256
h=√256
h=16cm
b=2*16
=32cm
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Answered by
0
Answer:
Step-by-step explanation:
If ABCD is llgram and ED and FC are the height
Join the diagnols BD and AC
In ∆ABD
1/2*AB*ED_eq 1
In ∆ BCD
1/2*CD*BF_eq 2
AB=2DE
CD=2BF
1/2*2DE*DE+1/2*2BF*BF=
512cm²
DE²+BF²=512cm²
DE=BF
DE²+DE²=512cm²
2DE²=512cm²
DE²=512/2cm²
DE²=256
DE=√256
DE=16cm
AB=2DE
AB=2(16)
AB=32cm
Therefore the
Height=16cm
Base=32cm
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