Math, asked by RaviyadV, 1 year ago

the base of parallelogram is twice its height if the area of parallelogram is 512 CM square find the base and height​

Answers

Answered by kithumonu
18

Answer:16

Step-by-step explanation:

Area of parallelogram =bh

base(b)=2*h

So, 2h*h=512

h^2=512/2

h^2=256

h=√256

h=16cm

b=2*16

=32cm

Got it?!

Answered by amirdavarshinimr
0

Answer:

Step-by-step explanation:

If ABCD is llgram and ED and FC are the height

Join the diagnols BD and AC

In ∆ABD

1/2*AB*ED_eq 1

In ∆ BCD

1/2*CD*BF_eq 2

AB=2DE

CD=2BF

1/2*2DE*DE+1/2*2BF*BF=

512cm²

DE²+BF²=512cm²

DE=BF

DE²+DE²=512cm²

2DE²=512cm²

DE²=512/2cm²

DE²=256

DE=√256

DE=16cm

AB=2DE

AB=2(16)

AB=32cm

Therefore the

Height=16cm

Base=32cm

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