The base of parallelogram with the area 154.4cm^2 and height 15 cm is________.(round off the tenths place in the answer)
Answers
Question :
The base of parallelogram with the area 154.4 cm² and height 15 cm is ________.
Answer :
Given :
Area Of Parallelogram - 154.4 cm²
Height of parallelogram - 15 cm
To Find :
Base of Parallelogram
Formula To Find :
Area Of Parallelogram = b × h
b = base
h = height
Solution :
⟶ Area = b × h
⟶ 154.4 = b × 15
⟶ b = 154.4 / 15
⟶ b = 10.29
⟶ b = 10.29 = 10.3
∴ Base Of Parallelogram = 10.29 (10.3) cm
Area = b × h
154.4 = 10.29 × 15
154.4 = 154.4
KNOW MORE :
Formulas To Find Area :
Circle = πr²
r = radius of the circle
Triangle = ½ × b × h
b = base, h = height
Square = a ²
a = length of side
Rectangle = l × b
l = length, b = breadth
Parallelogram = b × h
b=base, h=vertical height
Trapezium = ½(a+b) × h
a and b are the length of parallel sides,
h = height
\huge \sf{ \underline{ \underline{Question :}}}
Question:
The base of parallelogram with the area 154.4 cm² and height 15 cm is ________.
\huge \sf{ \underline{ \underline{Given :}}}
Given:
Area Of Parallelogram - 154.4 cm²
Height of parallelogram - 15 cm
\huge \sf{ \underline{ \underline{To \: Find :}}}
ToFind:
Base of Parallelogram
\huge \sf{ \underline{ \underline{Solution:- }}}
Solution:−
\bf \rightarrow \: Area = b × h→Area=b×h
\bf \rightarrow154.4 = b × 15→154.4=b×15
\bf \rightarrow \: b = \frac{ 154.4 }{15}→b=
15
154.4
\bf \rightarrow \: b = 10.29→b=10.29
\bf \rightarrow b = 10.29 = 10.3→b=10.29=10.3
\sf \: ∴ Base \: Of \: Parallelogram = 10.29 (10.3) cm∴BaseOfParallelogram=10.29(10.3)cm
Area = b × h
154.4 = 10.29 × 15
154.4 = 154.4
KNOW MORE ✔✔
\sf \: Formulas \: To \: Find \: \: Area =FormulasToFindArea=
\sf \: Circle = πr²Circle=πr²
\sf \: Triangle = ½ × b × hTriangle=½×b×h
\sf \: Square = side \times sideSquare=side×side
\sf Rectangle = l × bRectangle=l×b
\sf \: Parallelogram = b × hParallelogram=b×h
\sf \: Trapezium = ½(a+b) × hTrapezium=½(a+b)×h