the base of radii of two right circular cone of the same height are in the ratio 2 is to 3 find the ratio of their volume
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Ratio of their radii= 2:3
Let their radii be 2x and 3x respectively
Volume of 1st cone=1/3π(2x)^2h
Volume of 2nd cone=1/3π(3x)^2h
V1/V2=1/3π(2x)^2h / 1/3π(3x)^2h
=4x^2/9x^2
4:9
Let their radii be 2x and 3x respectively
Volume of 1st cone=1/3π(2x)^2h
Volume of 2nd cone=1/3π(3x)^2h
V1/V2=1/3π(2x)^2h / 1/3π(3x)^2h
=4x^2/9x^2
4:9
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Answer:
Step-by-step explanation:
let the radius of cones be 2x and 3x =(V1) volume ofonecone=1/3πr²h =1/3π(2x)²h =(V2)volume of second cone=1/3πr²h =1/3π(3x)²h =∴V1/V2=1/3π(2x)²h ÷ 1/3π(3x)²h =(2x)²/(3x)² =4x²/9x² =4/9 4:9
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