The base of rectangular vessel measured 10cm to 18cm water is poured into 4cm.what is the pressure on the base of vessel?
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Answer :- pressure
pressure=40kg/m^2
pressure=40kg/m^2Thrust
pressure=40kg/m^2Thrust=0.72kg
pressure=40kg/m^2Thrust=0.72kgExplanation:
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m=40 kg/m square
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m=40 kg/m squareThrust or force=pressure*area
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m=40 kg/m squareThrust or force=pressure*area=(40kg/m square)*(10/100)*18/100)
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m=40 kg/m squareThrust or force=pressure*area=(40kg/m square)*(10/100)*18/100)=(400*18)/(10000)
pressure=40kg/m^2Thrust=0.72kgExplanation:pressure=density*depth=(1000kg/m cube)*(4/100)m=40 kg/m squareThrust or force=pressure*area=(40kg/m square)*(10/100)*18/100)=(400*18)/(10000)=72/100=0.72 kg
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