Question

the base of right angle triangle measures 48 cm and its hypotenuse measures 50 cm find the area of the triangle

Answer 1

Hey


Case of right angled triangle :-

base = 48cm
hypotenuse= 50cm .

By Pythagoras theorem , we get

${h}^{2} = {b}^{2} + {p}^{2}$
So ,

${p}^{2} = {h}^{2} - {b}^{2}$

$= > {p}^{2} = {50}^{2} - {48}^{2}$


$= > {p}^{2} = 2500 - 2304$


$= > {p}^{2} = 196$


$= > p = \sqrt{196}$


$= > p = 14$
So ,

Perpendicular = 14 cm .

Now area of triangle = 1 / 2 * b * p
= 1 / 2 * 48 * 14
= 48 * 7
= 336 cm²


thanks :)

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Answer 2

Hi there !

Here's your answer

Let the triangle have vertices A, B and C( Diagram in attachment )
‌C
/ ।
/ ।
/_ । A
B

AB = 48cm
CB = 50cm

Since the triangle is a right angled triangle , the side AC can be found by using the PYTHAGORAS THEOREM

So,

(AB)² + (AC)² = (CB)²

(48)² + (AC)² = (50)²

(AC)² = (50)² - (48)²

(AC)² = 2500 - 2304

(AC)² = 196

$ac = \sqrt{196}$

AC = 14cm

since it is a right angled triangle ,in which AC is perpendicular to the base , it will be the height

So,
Base = 48cm
Height = 14cm

Area of triangle = ½ × base × height

$= \frac{1}{2} \times 48 \times 14$
= 336cm²

So,
the area of triangle is 336cm²