The base of right angled triangle 48 and its hypotenuse measure 50cm . Find the area of triangle
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5
by Pythagoras theorem,
hypotenuse 2=side1^2+side^2
(50)^2=(48)2+side^2
2500=2304+side^2
side2^2=2500-2304
side2^2=196
side2=14
now, area of a triangle=1/2×b×h
=1/2×48×14
=336cm square
hypotenuse 2=side1^2+side^2
(50)^2=(48)2+side^2
2500=2304+side^2
side2^2=2500-2304
side2^2=196
side2=14
now, area of a triangle=1/2×b×h
=1/2×48×14
=336cm square
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wlc
Answered by
4
P²+B²=H²
P=√50²-48²
P=√196
P=14
Area of right angle triangle is ab/2
Then, 48×14/2=336
P=√50²-48²
P=√196
P=14
Area of right angle triangle is ab/2
Then, 48×14/2=336
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