the base of right angled triangle measure 48 cm and its hypotenuse measure50 cm find the area of triangle
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Hey mate here is ur ans
first step
we get the height
by using Pythagoras theorem
h=root of (50²-48²)=root of (2500-2304)
=root of(196)=14cm
area of right angled triangle =1/2*b*h=1/2*48*14=336cm²
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hope it helps you frnd
first step
we get the height
by using Pythagoras theorem
h=root of (50²-48²)=root of (2500-2304)
=root of(196)=14cm
area of right angled triangle =1/2*b*h=1/2*48*14=336cm²
-----------
hope it helps you frnd
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Answered by
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By Pythagoras theorem,
Hypotenuse² = height² + base
Here,
50² = height² + 48²
(50)² - (48)² = Hieght²
2500- 2304 = height²
196 = height²
√196 = height
14 = height
×××××××××××××××××××××××
Then,
Area of right angled triangle = (base×height×1/2)
Here,
Area = (14×48×1/2)
Area = 14×24
Area = 336 cm²
I hope this will help you
(-:
Hypotenuse² = height² + base
Here,
50² = height² + 48²
(50)² - (48)² = Hieght²
2500- 2304 = height²
196 = height²
√196 = height
14 = height
×××××××××××××××××××××××
Then,
Area of right angled triangle = (base×height×1/2)
Here,
Area = (14×48×1/2)
Area = 14×24
Area = 336 cm²
I hope this will help you
(-:
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