The base of right pyramid is a square of side 10cm. If the height of the pyramid is 12cm, then find its
i)Slant height
ii) Lateral surface area (L.S.A)
iii) Total surface area (T.S.A)
iv) Volume
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Given :-
★Base of right pyramid = 10cm
★Height of the pyramid = 12cm
Find :-
★Slant height
★Lateral surface area (LSA)
★Total surface area (TSA)
★Volume
Solution :-
✯Area of the Base = 10×10 = 100cm²
✯perimeter of base = 10×4 = 40cm
✯Slant height = √r²+h²
⇛√12² + (10/2)²
⇛√12² + 5²
⇛√169
⇛13cm
Hence,The slant height of pyramid is 13cm
✯Curved surface area of pyramid =
⇛1/2 × perimeter of base × slant height
⇛1/2 × 40cm × 13cm
⇛260cm²
Hence, The curved surface area of pyramid is 260cm²
✯Total surface area of pyramid :-
Curved surface area + Area of base
⇛260cm² + 100cm²
⇛360cm²
Hence, The Total surface area of pyramid is 360cm²
Volume of pyramid :-
⇛1/3×base(b)²× height(h)
⇛1/3 × (10cm)² × 12cm
⇛1/3×100×12cm
⇛400cm³
Hence, The volume of pyramid is 400cm³
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