Question

The base of right triangle is 7/2 and it's altitude is 4/7. Find the area of rectangle.

Answer 1

Answer:

Step-by-step explanation:

Two right triangles = one rectangle

For rectangle base of the right triangle is breadth and altitude is length

area of the rectangle = length x breadth  = 4/7 x 7/2 = 2 square units

Answer 2

QuestioN :

The base of right triangle is 7/2 and it's altitude is 4/7. Find the area of rectangle.

GiveN :

• Base (B) = 7/2
• Height (H) = 4/7

To FinD :

• Area of Triangle

Solution :

Use formula for Area of triangle :

$\leadsto \boxed{\sf{Area \: = \: \dfrac{1}{2} \: \times \: Base \: \times \: Area}} \\ \\ \implies \rm{Area \: = \: \dfrac{1}{2} \: \times \: \dfrac{\cancel{7}}{\cancel{2}} \: \times \: \dfrac{\cancel{4}}{\cancel{7}}} \\ \\ \implies \rm{Area \: = \: \dfrac{1}{\cancel{2}} \: \times \: \dfrac{\cancel{2}}{1}} \\ \\ \implies \rm{Area \: = \: 1} \\ \\ \underline{\sf{\therefore \: Area \: of \: triangle \: is \: 1 \: unit^2}}$

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As, we know that two right angle triangles will form a rectangle,

$\implies \rm{Area \: of \: Rectangle \: = \: 2(Area \: of \: triangle)} \\ \\ \implies \rm{Area \: = \: 2(1)} \\ \\ \implies \rm{Area \: = \: 2} \\ \\ \underline{\sf{\therefore \:Area \: of \: rectangle \: is \: 2 \: unit^2}}$