the base of the isosceles triangle is 24 cm area is 192 cm. find the perimeter
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8
Formula of area of triangle is 1/2 X base X height
Hence 1/2 X 24 X h = 192
We get h as 16 cm
Now in an isoceles triangle, the HT, half of base and the equal sides form and right angled triangle. So using Pythagoras,
16^2 + (24/2)^2 = side ^2
We get the side as 20 cm.
Now perimeter will be 24+20+20 = 64 cm
Hence 1/2 X 24 X h = 192
We get h as 16 cm
Now in an isoceles triangle, the HT, half of base and the equal sides form and right angled triangle. So using Pythagoras,
16^2 + (24/2)^2 = side ^2
We get the side as 20 cm.
Now perimeter will be 24+20+20 = 64 cm
Answered by
6
Be =24
Area=192
Altitude = 24×x×1/2=192
24×x=192×2
24 ×x=384
x=384/24
x=16
Height of the triangle divides the isosceles triangle into two right triangles
The we have 16^2×24/2^2=AB^2
256+144=AB^2 =400
Therefore AB=20
Perimeter of the triangle =side+side +side =20+20+24=64
Area=192
Altitude = 24×x×1/2=192
24×x=192×2
24 ×x=384
x=384/24
x=16
Height of the triangle divides the isosceles triangle into two right triangles
The we have 16^2×24/2^2=AB^2
256+144=AB^2 =400
Therefore AB=20
Perimeter of the triangle =side+side +side =20+20+24=64
chattni13:
perimeter of the isosceles triangle
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