Question

The base of the parallelogram is thrice it's area is 867 m2 , find the length of the base and height of the parallelogram.

Answer 1

The area of the parallelogram = 867m
B × H = 867
3x × x = 867
3x2 = 867
x2 = 867/3
x2 = 289
x = squares root of 289
x = 17
Base of the parellelogram = 3x
= 3 × 17
= 51
Height of the parellelogram = x = 17

Answer 2

Let the height of a parallelogram be "$x$".

and, the base of a parallelogram in thrice its height.i.e, "$3x$".

Given :

The Area of parallelogram,

= $867 \ m^2$

To Find :

The base of parallelogram = ?

The height of parallelogram = ?

Solution :

As we know,

The Area of parallelogram = base × height

On putting the given value in the above formula, we get

$867=3x\times x\\\\867=3x^2\\\\x^2=289\\\\x=\sqrt{289}\\ \\x=17$

Now,

The height of parallelogram = $17 \ m$

The base of parallelogram = $3\times 17$ = $51 \ m$