The base of the parallelogram is thrice its height if the area of the parallelogram is 972cm. find the base and height of the parallelogram ??
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The values of height and base is to found.Lets assume that ,
height , h = a
Base , b = 3 a
As it is given that the base of the parallelogram is 3 times the height of the parallelogram.
Area of parallelogram = bh = 972 cm²
i.e,
a × 3 a = 972
3 a² = 972
a² = 972 ÷ 3
a ² = 324
a = √324
a = 18 cm
∴ height = a = 18 cm
base = 3a= 3 ×18 = 54 cm
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height , h = a
Base , b = 3 a
As it is given that the base of the parallelogram is 3 times the height of the parallelogram.
Area of parallelogram = bh = 972 cm²
i.e,
a × 3 a = 972
3 a² = 972
a² = 972 ÷ 3
a ² = 324
a = √324
a = 18 cm
∴ height = a = 18 cm
base = 3a= 3 ×18 = 54 cm
Please mark brainliest ...
Anonymous:
Please mark brainliest ....
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Answer:
Height = 18 cm and Base = 54 cm
Explanation:
Let the common multiple be x
Therefore, The Base of Parallelogram is 3x
We know that,
Area = Base * Height
Area = 3x * Height
972 = 3x * Height
x = 972/3
x = 324
√324 = x
x = 18 cm
Therefore, Height of Parallelogram is 18cm and it's base is 18 * 3 = 54 cm.
Therefore:
Height = 18 cm
Base = 54 cm
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