Question

the base of the parallelogram is twice its height the area of a parallelogram is 512 CM square find the base and height​

Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

•The base of the parallelogram is twice its height.

•The area of a parallelogram is 512 cm².

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

•The base of the parallelogram

•The height of the parallelogram

$\;\;\underline{\textbf{\textsf{ Formula used :-}}}$

$\bigstar{\underline{\boxed{\sf\green{Area \:of \:parallelogram = Base \times</p><p>Height}}}}$

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

Let the height of parallelogram be x cm.

Given that,

The base of the parallelogram is twice its height.

Then,

• the base of parallelogram will be 2x cm.

We know that,

$\bigstar{\underline{\boxed{\sf\green{Area \:of \:parallelogram = Base \times</p><p>Height}}}}$

$\:\:\:\:\dag\bf{\underline \green{Putting\:the\:values:-}}$

$\longrightarrow \sf {512\:cm^2 = x \times 2x}$

$\longrightarrow\sf {x^2 = \cancel\dfrac{512}{2} }$

$\longrightarrow \sf {x^2 = 256\:cm^2}$

$\longrightarrow\large{\sf{\green{x = 16\:cm^2}}}$

$\:\:\:\:\dag\bf{\underline{\underline \green{Hence:-}}}$

•The base of the parallelogram = 16 cm

•The height of the parallelogram = 2 × 16 = 32 cm

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