Question

the base of the parallelogram is twice its height the area of a parallelogram is 512 CM square find the base and height

Answer 1

Answer:

GIVEN , TWICE BASE OF ||gm = HEIGHT OF ||gm

==> 2 BASE = HEIGHT

AREA OF PARALLELOGRAM = 512 CM²

 512 = BASE × HEIGHT

 512 = B × 2 B (∴ 2 BASE = HEIGHT )

512 =  2 B²

512/2 = B²

=> 256 = B²

==> √256 = B

==>  16 = BASE

HEIGHT ==> 16×2 ==> 32

Answer 2

${\mathbf {\blue{S}{\underline{\underline{olution:-}}}}}$

$\mathfrak{\underline{AnswEr:-}}$

• The base of the parallelogram = 16 cm
• The height of the parallelogram = 32 cm

$\mathfrak{\underline{Given:-}}$

• The base of the parallelogram is twice its height.
• The area of a parallelogram is 512 cm².

$\mathfrak{\underline{Need\:To\: Find:-}}$

• The base of the parallelogram = ?
• The height of the parallelogram = ?

${\mathbf {\blue{E}{\underline{\underline{xplanation:-}}}}}$

Let the height of parallelogram be x cm.

Then, the base of parallelogram will be 2x cm.

$\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}$

$\bigstar{\underline{\boxed{\sf\purple{Area \:of \:parallelogram = Base \times Height}}}}$

$\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}$

$\longrightarrow \sf {512\:cm^2 = x \times 2x}$

$\longrightarrow\sf {x^2 = \cancel\dfrac{512}{2} }$

$\longrightarrow \sf {x^2 = 256\:cm^2}$

$\longrightarrow\large\boxed{\sf{\purple{x = 16\:cm^2}}}$

$\:\:\:\:\dag\bf{\underline{\underline \pink{Hence:-}}}$

• The base of the parallelogram = 16 cm

• The height of the parallelogram = 2 × 16 = 32 cm

$\rule{200}{2}$