Question

The base of the right angle triangle is 12 m and height is 8 m its area is​

Answer 1

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Answer 2

• As per the data given in the question, we have to find the area of the right-angle triangle.

       Given data- Base =$12m.$

        Height=$8m.$

        To find:- The area of the right-angle triangle.

        Solution:-

• In a right-angled triangle, one of the angle is 90 degree.

• In a right-angled triangle, the hypotenuse is the largest side. which is always the side opposite to the right angle.

• To find the base, we will use pythagoras theorem. $l^{2}+b^{2}=h^{2}.$

• The perimeter of a right triangle is the sum of the measures of all three sides.

• The area of a right triangle is  

$\Rightarrow A=\frac{1}{2} \times \text { base } \times \text { height. equation(1) }$

 Put the value of base and height in equation(1). we get,

$\begin{array}{l}\Rightarrow \frac{1}{2} \times12\times8\\\Rightarrow48m^{2} .\end{array}$

Hence, the area will be $48m^{2}.$