Question

the base of the right pyramid is a square of side 10 centimetres is the height of pyramid is 12 centimetres then find its slant height lateral surface area total surface area volume

Answer 1

Length of the side of the base(square)=10 cm
Height of the pyramid=12cm
As it is a right prism the line dropped from the top of the pyramid falls on the base making an angle of 90°
We can use the Pythagorean theorem
Slant height^2=base^2+height^2
Slant height ^2=5^2+12^2
Slant height=√25+144=√169=13
Total surface area=p*h/2+b
P is the perimeter of the base=4*10=40
H is the slant height=13
B is the area of a base=100
Total surface area=40*13/2+100=520/2+100=260+100=360
Total surface area=360cm^2
Lateral surface area=total surface area-area of base
=360-100=260cm^2

Answer 2

Answer:

Step-by-step explanation:slant height^2 = height ^2 + half of the length^2

=12^2+5^2

=144+25

=169

As it is slant height^2

Root of 169 which is 13cm

Lateral surface area = 1/2(perimeter of the base × slant height)

=1/2(40×13)

=1/2(520)

=260

Total surface area = lateral surface area + area of base

=260 + 10^2

=260+ 100

=360

Volume=1/3(area of base × height)

=1/3(100 × 12)

=1/3(1200)

=1200/3 =400

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