The base of the tiangle is 2x + 3 and height is 4x-2 if it's area is 30 sq.m.prepare a quadratic equation from given information
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Here,Area of triangle =30sq.m ,base=2x+3,height =4x-2,
Area of triangle=1/2×base×height
30=1/2×(2x+3)×(4x-2)
30=1/2×2x(4x-2)+3(4x-2)
30=1/2×8x^2-4x+12x-6
30=1/2×8x^2+8x-6
30×2=8x^2+8x-6
60+6=8x^2+8x
66=8x^2+8x
0=8x^2+8x-66
Ans : the required equation is 8x^2+8x-66=0
Area of triangle=1/2×base×height
30=1/2×(2x+3)×(4x-2)
30=1/2×2x(4x-2)+3(4x-2)
30=1/2×8x^2-4x+12x-6
30=1/2×8x^2+8x-6
30×2=8x^2+8x-6
60+6=8x^2+8x
66=8x^2+8x
0=8x^2+8x-66
Ans : the required equation is 8x^2+8x-66=0
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