The base of the traingle is 5cm longer than its altitude.If the area of the traingle is 18sq.cm then find its base and altitude?
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area of triangle = 1/2× base×height
=1/2×x×5+x = 18
=5x + xsquare =18
=xsquare + 5x = 18
bsquare - 4ac
25 + 144 = 169
x = -5+13/2 = 8/2 = 4cm
base = 5+ x=5+4=9cm
altitude = x = 4cm
=1/2×x×5+x = 18
=5x + xsquare =18
=xsquare + 5x = 18
bsquare - 4ac
25 + 144 = 169
x = -5+13/2 = 8/2 = 4cm
base = 5+ x=5+4=9cm
altitude = x = 4cm
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