Question

the base of triangle along x=2 and of length 2 area of triangle is 4 then locus of vertex​

Answer 1

Answer:

Step-by-step explanati

2

1

​  

×a∣h−a∣=a  

2

.

⇒h=−a or h=3a.

Hence, the combined equation of the pair of lines is (h+a)(h−3a)=0

(x+a)(x−3a)=0 is the required locus.