the base of triangle is 12 cm and its hypotenuse is 13 cm then find its height ?
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It is given that
ABC is a right angled triangle
BC = 12 cm and AB 13 cm
Using the Pythagoras theorem
AB
2
=AC
2
+BC
2
Substituting the values
13
2
=AC
2
+12
2
so we get
AC
2
=169−144=25
AC=5
area=
2
1
×12×5=30cm
2
Perimeter=12+13+5=30cm
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