Question

The base of triangle is 6cm longer than its altitude of the area of triangle is 56sqcm then find its base and altitude

Answer 1

let height be x
then breadth is 6+x
now 1/2 *b*h=56 after puting values we get 6x+x^2 - 112=0 x+14x-8x-112=0 x(x+14)-8(x+14)=0 (x+14)(x-8)=0 so x=8(it cant be negative so we discard 14) so breadth=14

Answer 2

let the height be x
therefore, base = 6+x
area of triangle = 56 sqcm
as per question
1/2*b*h = area of triangle
1/2*x+6*x = 56 sqcm
x2 + 6x/2 =56
x2 + 6x = 56×2 = 112
x + 6 = 112/ x
by trial and error method
x = 7 cm
x + 6 = 13 cm