Question

The base perimeter of a cuboidal tank is 10m. if the lateral surface area of the tank is 5m2, then the height of the tank is
(a)4m
(b)1m
(c)10m
(d)500cm
no spamming, give the correct answer!​

Answer 1

Answer:

• Height of the tank = 50 cm

Step-by-step explanation:

Given that:

• The base perimeter of a cuboidal tank is 10 m.
• The lateral surface area of the tank is 5 m².

To Find:

• Height of the tank.

Formula used:

• Lateral surface area of cylinder = 2πrh
• Perimeter/Circumference of a circle = 2πr

Here,

• Radius is denoted as r.
• Height is denoted as h.

Finding the height:

Lateral surface area = Perimeter × Height

→ 5 m² = 10 m × Height

→ 5 m × 1 m = 5 m × 2 × Height

• Both sides 5 m cancelled.

→ Height = (1 m)/2

→ Height = 0.5 m

Converting 0.5 m of height into cm:

∵ 1 m = 100 cm

∴ 0.5 m = (100 × 0.5) cm = 50 cm

Answer 2

Question :-

• The base perimeter of a cuboidal tank is 10m. if the lateral surface area of the tank is 5m^2, then the height of the tank is

(a)4m

(b)1m

(c)10m

(d)500cm

Answer

Given :-

• The base perimeter of a cuboidal tank is 10m.
• The lateral surface area of the tank is 5m^2,

To Find :-

• The height of the cuboidal tank.

Formula Used :-

$(1). \: \boxed{ \blue{ \bf \:Base \: Perimeter \: of \: cuboid = 2 (l+ b)\: }}$

$(2). \: \boxed{ \blue{ \bf \:Lateral \: surface \: area\: = 2(l + b) \times h }}$

$\boxed{ \blue{ \bf \:Lateral \: surface \: area \: = Base \: Perimeter \times h\: }}$

$\large\underline\purple{\bold{Solution :- }}$

It is

Given that

• Base Perimeter of cuboidal tank = 10 m

• Lateral surface area = 5 m^2.

• Let height of cuboidal tank be 'h' meter.

So,

Using formula,

Lateral Surface Area = Perimeter of Base × height

$\rm :  \implies \:5 = 10 \times h$

$\rm :  \implies \:h \: = \: \dfrac{5}{10} \: m$

$\rm :  \implies \:h \: = \: \dfrac{1}{2} \times 100 \: cm$

$\rm :  \implies \:h \: = \: 50 \: cm$

So, it implies

None of the option is correct.