the base qr of an equilateral triangle pqr with side 10cm lies along x axis such that midpoint of the base is the origin . then the
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Let (x,0) be the coordinates of R. Then
0 = -4+x/2
x = 4
Thus, the coordinates of R are (4,0).
Here, PQ = QR = PR and the coordinates of P lies on y axis . Let the coordinates of P be (0, y) Then, in the picture above
Given : the base qr of an equilateral triangle pqr with side 10 cm lies along x axis such that midpoint of the base is the origin .
To Find : Coordinate of q and r
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Solution:
qr lies on x axis
Hence q and r coordinates will be of form ( x , 0)
mid point is at origin Hence
Coordinates of q and r will be
( h, 0) and ( -h , 0)
Distance = |2h |
| 2h | = 10
=> h = ± 5
Hence coordinates of q and r will be ( 5, 0) and ( - 5 , 0)
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