Question

The base radius and height of a right circular cylinder are 5 cm and 10 cm respectively. It's curved surface area is ​

Answer 1

Answer:

This is the correct answer

Step-by-step explanation:

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Answer 2

Question :-

• The base radius and height of a right circular cylinder are 5 cm and 10 cm respectively. It's curved surface area is .

Given :-

• Base of the Cylinder = 5cm
• Height of the Cylinder = 10cm

To Find :-

• Curved Surface Area of Cyclinder.

Diagram :-

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{5cm}}\put(9,17.5){\sf{10cm}}\end{picture}$

Solution :-

★ Curved Surface Area of Cyclinder ★

${:} \longrightarrow \sf{\sf{Curved\: Surface \:Area\: of\: Cyclinder\: = \: 2 \pi \: r \:h }}$

${:} \longrightarrow \sf{\sf{Curved\: Surface \:Area\: of\: Cyclinder\: = \: 2 \times \dfrac{22}{7} \: \times \: 5\: \times \: 10 }}$

${:} \longrightarrow \sf{\sf{Curved\: Surface \:Area\: of\: Cyclinder\: = \: \ \dfrac{44 \: \times \: 50}{7} \: }}$

${:} \longrightarrow \sf{\sf{Curved\: Surface \:Area\: of\: Cyclinder\: = \: \ \dfrac{2200}{7} \: }}$

${:} \longrightarrow \sf{\bf{Curved\: Surface \:Area\: of\: Cyclinder\: = \: \ 314.28\: cm^{2} \: }}$

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So , C.S.A of Cyclinder is 314.28cm²

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★ Additional Info :

• T.S.A of cylinder = 2πrh + 2πr²
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

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