Math, asked by spcplayz, 21 days ago

The base radius and length of a cylindrical road roller are 0.9 m and 7 m respectively. What is the minimum number of revolutions required to flatten a road of width 8 m and length 5.2 km

Answers

Answered by asfandyarchandiosaha

0

Answer:

h=1.4m r=100cm=1m

CSA=2TTrh=2x 7

22

x1x1.4=8.8m

2

Total area =125x2 -= 2500m

2

No. of revolutions =

8.8

2500

=284.09.

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