The base radius and length of a cylindrical road roller are 0.8 m and 7 m respectively. What is the minimum number of revolutions required to flatten a road of width 7 m and length 4.4 km?
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Step-by-step explanation:
h=1.4m
r=100cm=1m
CSA=2πrh=2×
7
22
×1×1.4=8.8m
2
Total area =125×2−=2500m
2
No. of revolutions =
8.8
2500
=284.09.
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