Question

The base radius and neight of a night crcular cylinder are 14 cm and 5 cm respectively its curved surface is

Answer 1

Answer:

Given :-

• The base radius and height of a right circular cylinder are 14 cm and 5 cm respectively.

To Find :-

• What is the curved surface area of a cylinder.

Formula Used :-

$\boxed{\bold{\large{C.S.A\: of\: a\: cylinder\: =\: 2{\pi}rh}}}$

where,

• C.S.A = Curved Surface Area
• r = Radius
• h = Height

Solution :-

Given :

• Radius = 14 cm
• Height = 5 cm

According to the question by using the formula we get,

⇒ $\sf C.S.A =\: 2 \times \dfrac{22}{\cancel{7}} \times {\cancel{14}} \times 5$

⇒ $\sf C.S.A =\: 2 \times 22 \times 2 \times 5$

⇒ $\sf C.S.A =\: 2 \times 44 \times 5$

⇒ $\sf C.S.A =\: 88 \times 5$

➠ $\sf\bold{\red{C.S.A =\: 440\: c{m}^{2}}}$

$\therefore$ The curved surface area of a cylinder is 440 cm² .

Answer 2

$\huge\bf{Answer :- }$

Given :-

• Radius of the base of circular cylinder = 14cm

• Height of the Cylinder = 5cm

To Find :-

• Curved surface area of the Cylinder

Formula :-

$\large\sf\fcolorbox{red}{pink}{Curved surface area of cylinder = 2πrh}$

where,

• r = Radius of the base of cylinder

• h = height of the Cylinder

Solution :-

By substituting values According to the formula,

⇒ 2×22/7×14cm×5cm

⇒ 44/7×14cm×5cm

⇒ 88cm×5cm

➥ 440cm²

Hence, The Curved surface area of the Cylinder is 440cm²