Question

The base radius of a hemispherical bowl is 12 cm. Find the cost of painting the inner part of the bowl at the rate of Rs 10 per cm^2 ​

Answer 1

Answer:

TSA = π(3R

2

+r

2

)

=

7

22

(3×6

2

+5

2

)cm

2

=

7

22

×133cm

2

Cost = Rs

7

22

×133×

100

7

= Rs 25.26

Answer 2

Step-by-step explanation:

$\sf\huge\bold\red{༄❁hii❁❁❁❁༄ }༄❁hii❁❁❁❁༄ \sf\huge\\purple{༄❁❁❁❁❁༄ }$

Mark as brainlist please