the base ( unequal side ) of an isosceles triangle is 4cm and its perimeter is 20cm. find its area.
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Answer :
- Area is 4√15 cm²
Given :
- The base (un equal side ) of an iscoscles triangle is 4cm
- Perimeter is 20cm
To find :
- Area
Solution :
- Let the sides of triangle be a and a&b
- b = 4cm
Given that,
- Perimeter = 20cm
》a + a + b = 20
》2a + 4 = 20
》2a = 20 - 4
》2a = 16cm
》a = 16/2
》a = 8cm
As we know that,
- Semi - Perimeter = Perimeter/2 = 20/2 = 10cm
And also, we know that,
- Area = √s(s - a) (s - b) (s - c)
where, s is 10cm and a is 8cm
》Area = √s(s - a) (s - b) (s - c)
》Area = √10(10 - 8) (10 - 4) (10 - 8 )
》Area = √10 × 2 × 6 × 2
》Area = √2 × 5 × 2 × 2 × 3 × 2
》Area = 4√15 cm²
Hence, Area is 4√15 cm²
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