Question

the basis of an isosceles triangle is 1 by 3 cm the perimeter of the triangle is 42 by 15 cm what is the length of ether of the remaining equal side​

Answer 1

Answer:

Let ∆ ABC be an isosceles triangle.

Base = BC = 4/3

Let AB = X

So, BC = X

Given,

2

perimeter = 4----- cm

15

4×15+2 / 15 = 6+2 / 15= 62/15