The battery has an internal resistance of 0.5 ohm
What is the current in the circuit?
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Answer:The resistance of the resistors which are in parallel =1/2+1/2=1 ohm
The resistance of resistors that are in parallel =1/2+1/2=1 ohm
The two resistance of resistors is 1 and 1 .Now there are three resistors that are in series (1,1,1) ,add them.
Resistance is 3 ohm.
Add the resistors that are in parallel =1/3+1/3=2/3 and we know that the formula for calculating the resistance of resistors that are in parallel is 1/r=1/r+1/r........
We want r, so we will do reciprocal of 1/r that is r=3/2=1.5 ohm and then add 0.5to the resistance 1.5(1.5+0.5=2) and we get 2 ohm
Now current =V/R ,1.5/2=0.75 Ampere.
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