Question

The battery is pushing 2.25mA through the 2kΩ resistor. What is the voltage of the battery?

Answer 1

Answer:

We know that

V=IR

So, Here given

----------------

I=2.25/1000A

R=2000ohm

so, V=2.25/1000×2000

V=4.5V

So, the battery is of 4.5V .

Answer 2

Answer:

4.5 V

Explanation:

Current = 2.25 * $10^{-3}$ A

Resistance = 2 *  $10^{3}$

Voltage = Current * Resistance

Voltage = 2.25 * $10^{-3}$ * 2 *  $10^{3}$ Ω

= 2.25 * 2

= 4.5 V