The battery of 10 v is connected to a resistance of 20 ohm through a variable resistance r. The amount of charge which was passed in the circuit in 4 min, if the variable resistance r
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Answered by
1
Answer:
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Answered by
0
Answer:
Answer is 120loge 2c
Explanation:
Given,
V=10V
R=20ohm
dt
dR
=5
min
ohm
=
60
5
=
12
1
sec
ohm
t=4min
To Find,
q→ Amount of charge
So we know,
I=
dt
dR
=
R
V
dR
dq
⋅
dt
dR
=
R
V
⇒dq=
R
V
⋅
dt
dR
dt
⇒dq=
R
Vdt
⋅
dt
dR
⇒dq=12V⋅
dt
dR
[∵
dt
dR
=
12
1
]
⇒q=12V∫
20
40
R
dR
[∵∫
x
1
dx=logx]
⇒q=12⋅(10)∫
20
40
R
1
dR
⇒q=120(log
e
40−log
e
20)[∵loga−logb=log
b
a
]
⇒q=120log
e
2C
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