Physics, asked by debdaskarmakar1798, 9 months ago

The beam and pans of a balance have negligible mass. An object weight . When placed in one pan and when placed in the other pan. The weights of the object is.

Answers

Answered by Dhruv4886
8
  • The weight (W) of the object is \sqrt{W1 . W2}.

Given-

  • Mass of beam and pan is negligible.
  • Weight of object in one pan = W₁
  • Weight of the object in another pan = W₂

When object weights W₁ then

W₁ . l₁ = W . l₂          (i)

When object weights W₂ then by balancing torque we get -

W. l₁ = W₂ . l₂          (ii)

From (i) and (ii) we get

W₁/W = W/W₂

W = \sqrt{W1 . W2}

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