Math, asked by kamu13, 1 year ago

The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is​

Answers

Answered by hxxfx7
3

Answer:

can I please have the question briefly

Answered by KailashHarjo
1

The bearing of BC is 96° 58'.

Given:

The bearing of line AB is 152° 30'.

The angle ABC measured clockwise is 124° 28'.

To Find:

The bearing of BC.

Solution:

Given, that we have the bearing of AB = 152° 30'

and the angle at B = 124° 28'

(A bearing taken in the direction that is completely the opposite of the direction being traveled is called a Back Bearing.)

We know, Back bearing= forward bearing + included angle

Hence, back bearing of BC = CB = 152° 30' + 124° 28' = 276° 58'

Since, we are supposed to find the forward bearing of BC,

= Back bearing - 180°

(To obtain the back bearing, we add or subtract 180 degrees from the forward bearing.)

= 276° 58` - 180° = 96° 58'

Hence, the bearing of BC is 96° 58'.

#SPJ3

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