The bearing of line AB is 152° 30' and angle ABC measured clockwise is 124° 28'. The bearing of BC is
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Answer:
can I please have the question briefly
The bearing of BC is 96° 58'.
Given:
The bearing of line AB is 152° 30'.
The angle ABC measured clockwise is 124° 28'.
To Find:
The bearing of BC.
Solution:
Given, that we have the bearing of AB = 152° 30'
and the angle at B = 124° 28'
(A bearing taken in the direction that is completely the opposite of the direction being traveled is called a Back Bearing.)
We know, Back bearing= forward bearing + included angle
Hence, back bearing of BC = CB = 152° 30' + 124° 28' = 276° 58'
Since, we are supposed to find the forward bearing of BC,
= Back bearing - 180°
(To obtain the back bearing, we add or subtract 180 degrees from the forward bearing.)
= 276° 58` - 180° = 96° 58'
Hence, the bearing of BC is 96° 58'.
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