Math, asked by vk929108, 10 months ago

the Bell of School A rings every 30 minutes whereas the bell of school B every 40 minutes both the bells rang together at 10:00 a.m. at what time will both of them together again​

Answers

Answered by AaravpandeyAV1306
4

Answer:

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Step-by-step explanation:

You take the LCM of both the numbers first

LCM of 60 and 40 is

60 = 2*3*5*2

40 = 2*2*5*2

LCM = 2*2*2*5*3

= 120

that means the bells will strike together after 120 minutes that is 2 hours

that's is 10am.

Answered by RvChaudharY50
1

Given :- The Bell of School A rings every 30 minutes whereas the bell of school B every 40 minutes both the bells rang together at 10:00 a.m. at what time will both of them together again ?

Solution :-

we know that, the bell will rings again at the same time will be LCM of their individual time.

so, Prime factors of 30minutes and 40 minutes :-

→ 30 = 2 * 3 * 5

→ 40 = 2 * 2 * 2 * 5

→ LCM = 2 * 2 * 2 * 3 * 5 = 120 minutes.

therefore, we can conclude that, both bells will ring again together after 120 minutes or 2 hours.

hence,

→ both of them together again at = 10AM + 2 hours = 12:00 noon.

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