Question

The best answer will be mark as brainliest and the user will be followed by me.

AND MY ALL FRIENDS PLEASE REPORT THE UNUSUAL ANSWERS BECAUSE I AM NOT HERE TILL EVENING. ​

Answer 1

Answer:

Hey friend,

I have solved One part for you,

Hope that you have understood the formula,

And can apply it to another part yourself,

$i)3x - 4y = 7 \\ = > 3x = 7 + 4y \\ = > x = \frac{7 + 4y}{3} ..........(1) \\ 5x + 2y = 3 ..........(2) \\ putting \: (1) \: into \: (2) \\ 5( \frac{7 + 4y}{3} ) + 2y = 3 \\ = > \frac{35 + 20y}{3} + 2y = 3 \\ = > \frac{35 + 20y + 6y}{3} = 3 \\ = > {35 + 20y + 6y } = 3 \times 3 = 9 \\ = > 35 + 26y = 9 \\ = > 26y = 9 - 35 = - 26 \\ = > y = \frac{ - 26}{26} = - 1 \\ = > x = \frac{7 + 4y}{3} = \frac{7 + ( - 4)}{3} \\ = > x = \frac{3}{3} = 1$

HOPE IT HELPS YOU.

PLEASE MARK AS BRAINLIEST...