Question

The binding energies per nucleon for
deuterium and helium are 1.1 MeV and 7.0
MeV respectively. The energy in joules will
be liberated when 10% deuterons take part in
the reaction
1) 18.88x10-?) 2) 18.88x10-)
3) 18.88x10-7J 4) 18.88x10-10 J​

Answer 1

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• 1.89 x 10-⁶

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If two deuterium nuclei react to form a single helium nucleus

H + H → He + Q

Energy released Q=4 ×7 × (− 2)× 2× 1.1= 23.6MeV

10⁶ deuterium atom will have 10⁶÷ 2 Helium atom as a result

==>Total energy liberated is ;

E = (10⁶÷2) x 23.6

===>11.8 x 10¹²eV

1eV = 1.6 x 10-¹⁹ J

11.8 x 10¹²eV = 11.8 x 10¹² x 1.6 x 10-¹⁹

==>{1.89 x 10-⁶}

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