the binding energy of a satellite is 30127×10ration9 J. Find its energy
Answers
Answer:
Data : , = 1000 kg, h = 1600 km =1.6×106m,R=6.4×106=1.6×106m,R=6.4×106 m
G = 6.67×10−11N.m2/kg2M=6×1024Kg6.67×10-11N.m2/kg2M=6×1024Kg
For the satellite
(i) the total energy , E=GMm2(R+h)=−6.67×10−11(6×1024)(1000)2(6.4+1.6)×106E=GMm2(R+h)=-6.67×10-11(6×1024)(1000)2(6.4+1.6)×106
=2.502k×1010J=2.502k×1010J
(ii) The binding energy = - E = 2.502×1010J2.502×1010J
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