Question

The binding energy of a satellite revolving around planet in a circular orbit is 3 × 10 9 J.
Its kinetic energy is ________

Answer 1

Answer:

here is the answer......

Answer 2

Explanation:

Given The binding energy of a satellite revolving around planet in a circular orbit is 3 × 10 9 J.Its kinetic energy is

• Due to the orbital motion the kinetic energy of a satellite is revolving around the planet in circular orbit.
• So K.E = GMm / 2r
• Now the energy required to remove the satellite from its orbit around the planet to infinity is the Binding energy.
• So Binding energy = energy of satellite at infinity – energy of satellite in its orbit
•                                = 0 – (- GMm / 2r)
•        Or Binding energy = GMm / 2r
• From both the equations we have K.E = B.E
• Therefore the binding energy of satellite revolving around the planet in a circular orbit is  3 x 10^9 J

Reference link will be

https://brainly.in/question/12971420