Question

The binding energy of deutron (1h 2 ) is 1.15 mev per nucleon and an alpha particle ( 2he4 ) has a binding energy of 7.1 mev per nucleon. Then in the reaction 1h 2 + 1h 2 2he4 + q the energy q released in mev is

Answer 1

Answer:

Given, 1H2 + 1H2 → 2H4 + Q The total binding energy of the deutrons = 4 × 1.15 = 4.60 MeV The total binding energy of alpha particle = 4 × 7.1 = 28.4 MeV The energy released in the process = 28.4 – 4.60 = 23.8 MeV. Read more on Sarthaks.com - https://www.sarthaks.com/424018/the-binding-energy-of-deuteron-2-1h-is-1-15-mev-per-nucleon-and-an-alpha-particle-2-4-he