Question

The binding energy of the hydrogen atom in its ground state is 13.6 ev the energy of he + ion in the first excited state will be

Answer 1

Answer:

13.6 j

Explanation:

Ionization energy can be calculated using the formula:

E=-13.6 \frac{z^{2}}{n^{2}}

z is the mass number, n is the number of orbit.

For a hydrogen atom , H

z is 1 and n is 1 as it is for first excited state.

So energy comes out to be -13.6 J

And for a helium atom, He:

z is 2 and n is 2.

As here it need to be calculated for the second excited state.

So energy value comes out to be:

E= -13.6 \frac{2^{2}}{2^{2}}

E= -13.6 J.