Question

The binding energy per nucleon for ²₁H and ⁴₂He
respectively are 1.1 MeV and 7.1 MeV. The energy released
in MeV when two ²₁H nuclei fuse to form ⁴₂He is
(a) 4.4 (b) 8.2 (c) 24 (d) 28.4

Answer 1

Answer:

ANSWER

1

H

2

+

1

H

2

→

2

He

4

+ΔE

The binding energy per nucleon of a deuteron =1.1MeV

∴ Total binding energy = 2×1.1 =2.2MeV

The binding energy per nucleon of a helium nuclei =7MeV

∴ Total binding energy = 4×7=28MeV

∴ Hence, energy released

ΔE=(28−2×2.2) =23.6MeV

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