The binding energy per nucleon for deuteron
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it will be 1) 1.1 MeV
I hope it will be helpful to you
ptmythili02:
sir/ Mam, I want solution
Deuterium has a mass of 2.01410178 amu.
Hydrogen atom = 1 x 1.007825 amu = 1.007825 amu
Neutrons = 1 x 1.008665 amu = 1.008665 amu
2.016490 amu
Mass difference = theoretical mass - actual mass
= 2.016490 amu - 2.01410178 amu = 0.002388 amu
Calculating the binding energy per nucleon:
Binding energy -0.002388 amu x 931.5 Mev/amu
Nucleon 2 nucleons
= -1.1123 Mev/nucleon
Hydrogen atom = 1 x 1.007825 amu = 1.007825 amu
Neutrons = 1 x 1.008665 amu = 1.008665 amu
2.016490 amu
Mass difference = theoretical mass - actual mass
= 2.016490 amu - 2.01410178 amu = 0.002388 amu
Calculating the binding energy per nucleon:
Binding energy -0.002388 amu x 931.5 Mev/amu
Nucleon 2 nucleons
= -1.1123 Mev/nucleon
tick the brainly
is that okay
I think it is not correct . Can you please check and give information about the answer
please send a photo of answer
hey bro it is absolutely correct
just take 1.1MeV and minus sign is my mistake
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